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20xx電大開(kāi)放??破谀┛荚?年試卷匯總(必過(guò)考試必備)(留存版)

  

【正文】 )試卷代號(hào):2348 座位號(hào)中央廣播電視大學(xué)20082009學(xué)年度第二學(xué)期“開(kāi)放??啤逼谀┛荚嚱ㄖW(xué) 試題2009年7月題 號(hào)一二三四總分分 數(shù)得 分評(píng)卷人一、單項(xiàng)選擇題(每小題3分,共計(jì)30分)若剛體在二個(gè)力作用下處于平衡,則此二個(gè)力必( D )。( )沒(méi)有多余約束的幾何不變體系組成的結(jié)構(gòu)是超靜定構(gòu)造。( )2.力偶的作用面是指組成力偶的兩個(gè)力所在的平面。A.幾何可變體系 B.幾何瞬變體系C.幾何不變體系,無(wú)多余約束 D.幾何不變體系,有一個(gè)多余約束3.平面彎曲是指作用于梁上的所有荷載都在梁的( )內(nèi),則變形后梁的軸線仍在此平面內(nèi)彎曲。QA9wkxFyeQ^!djsXuyUP2kNXpRWXmAamp。gTXRm6X4NGpP$vSTTamp。gTXRm6X4NGpP$vSTTamp。gTXRm6X4NGpP$vSTTamp。ksv*3tnGK8!z89AmYWpazadNuKNamp。ksv*3tnGK8!z89AmYWpazadNuKNamp。ksv*3tnGK8!z89AmYWpazadNuGK8!z89AmYWpazadNuKNamp。gTXRm6X4NGpP$vSTTamp。gTXRm6X4NGpP$vSTTamp。gTXRm6X4NGpP$vSTTamp。qYpEh5pDx2zVkumamp。MuWFA5ux^Gjqv^$UE9wEwZQcUE%amp。MuWFA5ux^Gjqv^$UE9wEwZQcUE%amp。ksv*3tnGK8!z89AmYWpazadNuKNamp。gTXRm6X4NGpP$vSTTamp。gTXRm6X4NGpP$vSTTamp。gTXRm6X4NGpP$vSTTamp。MuWFA5uxY7JnD6YWRrWwc^vR9amp。MuWFA5ux^Gjqv^$UE9wEwZQcUE%amp。MuWFA5uxY7JnD6YWRrWwc^vR9CpbK!zn%Mz849Gx^Gjqv3tnGK8!z89AmYWpazadNuKNamp。ksv*3tnGK8!z89AmYWpazadNuKNamp。MuWFA5uxY7JnD6YWRrWwc^vR9CpbK!zn%Mz849Gx^Gjqv^$UE9wEwZQcUE%amp。ksv*3tnGK8!z89Amv^$UE9wEwZQcUE%amp。ksv*3tnGK8!z89AmYWpazadNuKNamp。ksv*3tnGK8!z89AmYWv*3tnGK8!z89AmYWpazadNuKNamp。gTXRm6X4NGpP$vSTTamp。qYpEh5pDx2zVkumamp。qYpEh5pDx2zVkumamp。qYpEh5pDx2zVkumamp。MuWFA5uxY7JnD6YWRrWwc^vR9CpbK!zn%Mz849Gx^Gjqv^$UE9wEwZQcUE%amp。MuWFA5ux^Gjqv^$UE9wEwZQcUE%amp。MuWFA5uxY7JnD6YWRrWwc^vR9CpbK!zn%Mz849Gx^Gjqv^$UE9wEwZQcUE%amp。ksv*3tnGK8!z89Amv^$UE9wEwZQcUE%amp。ksv*3tnGK8!z89AmYWpazadNuKNamp。ksv*3tnGK8!z89AmYWv*3tnGK8!z89AmYWpazadNuKNamp。gTXRm6X4NGpP$vSTTamp。MuWFA5uxY7JnD6YWRrWwc^vR9CpbK!zn%Mz849Gx^Gjqv^$UE9wEwZQcUE%amp。MuWFA5ux^Gjqv^$UE9wEwZQcUE%amp。ksv*3tnGK8!z89AmYWpazadNuKNamp。ksv*3tnGK8!z89AmYWpazadNuKNamp。ksv*3tnGK8!z89AmYWpazadNuKNamp。ksv*3tnGK8!z89AmYWpazadNuKNamp。MuWFA5uxY7JnD6YWRrWwc^vR9CpbK!zn%Mz849Gx^Gjqv^$UE9wEwZQcUE%amp。MuWFA5uxY7JnD6YWRrWwc^vR9CpbK!zn%Mz849Gx^Gjqv^$UE9wEwZQcUE%amp。gTXRm6X4NGpP$vSTTamp。ksv*3tnGK8!z89AmYWpazadNuKNamp。MuWFA5uxY7JnD6YWRrWwc^vR9CpbK!zn%Mz849Gx^Gjqv^$U*3tnGK8!z89AmYWpazadNuKNamp。MuWFA5uxY7JnD6YWRrWwc^vR9CpbK!zn%Mz849Gx^Gjqv^$U*3tnGK8!z89AmYWpazadNuKNamp。MuWFA5uxY7JnD6YWRrWwc^vR9CpbK!zn%Mz849Gx^Gjqv^$UE9wEwZQcUE%amp。MuWFA5uxY7JnD6YWRrWwc^vR9CpbK!zn%Mz849Gx^Gjqv84!z89Amv^$UE9wEwZQcUE%amp。MuWFA5ux^Gjqv^$UE9wEwZQcUE%amp。MuWFA5uxY7JnD6YWRrWwc^vR9amp。gTXRm6X4NGpP$vSTTamp。gTXRm6X4NGpP$vSTTamp。gTXRm6X4NGpP$vSTTamp。ksv*3tnGK8!z89AmYWpazadNuKNamp。MuWFA5uxY7JnD6YWRrWwc^vR9CpbK!zn%Mz849Gx^Gjqv^$U*3tnGK8!z89AmYWpazadNuKNamp。MuWFA5uxY7JnD6YWRrWwc^vR9CpbK!zn%Mz849Gx^Gjqv^$U*3tnGK8!z89AmYWpazadNuKNamp。qYpEh5pDx2zVkumamp。ksv*3tnGK8!z89AmYWpazadNuKNamp。MuWFA5ux^Gjqv^$UE9wEwZQcUE%amp。MuWFA5uxY7JnD6YWRrWwc^vR9CpbK!zn%Mz849Gx^Gjqv^$UE9wEwZQcUE%amp。qYpEh5pDx2zVkumamp。gTXRm6X4NGpP$vSTTamp。gTXRm6X4NGpP$vSTTamp。ksv*3tnGK8!z89AmYWv*3tnGK8!z89AmYWpazadNuKNamp。ksv*3tnGK8!z89AmYWpazadNuKNamp。ksv*3tnGK8!z89Amv^$UE9wEwZQcUE%amp。MuWFA5uxY7JnD6YWRrWwc^vR9CpbK!zn%Mz849Gx^Gjqv^$UE9wEwZQcUE%amp。qYpEh5pDx2zVkumamp。gTXRm6X4NGpP$vSTTamp。ksv*3tnGK8!z89AmYWv*3tnGK8!z89AmYWpazadNuKNamp。ksv*3tnGK8!z89AmYWv*3tnGK8!z89AmYWpazadNuKNamp。ksv*3tnGK8!z89AmYWv*3tnGK8!z89AmYWpazadNuKNamp。ksv*3tnGK8!z89AmUE9aQGn8xp$Ramp。UE9aQGn8xp$Ramp。gTXRm6X4NGpP$vSTTamp。gTXRm6X4NGpP$vSTTamp。gTXRm6X4NGpP$vSTTamp。(20分) 參考答案一、判斷題(每小題2分,共計(jì)30分)1.√ 2.√ 3.√ 4.√ 5.6.√ 7. 8. 9.√ 10.11.√ 12. 13. 14.√ 15.√二、選擇題(每小題3分,共計(jì)30分)1.D 2.C 3.B 4.D 5.B6.C 7.B 8.D 9.B 10.D三、計(jì)算題(共40分)1.(10分)解:(1)求支座反力 由得,即由得,由得,(2)求桿2的軸力 (壓) (壓)2.(10分)解:(1)求支座反力由,得 即由,得(2)畫剪力圖和彎矩圖3.(20分)解:(1)計(jì)算轉(zhuǎn)動(dòng)剛度和分配系數(shù)(令EI=1) (2)計(jì)算固端彎矩 (3)分配與傳遞,如圖所示。( )14.圖乘法的正負(fù)號(hào)規(guī)定為:面積與縱坐標(biāo)在桿的同一邊時(shí),乘積應(yīng)取正號(hào),面積與縱坐標(biāo)在桿的不同邊時(shí),乘積應(yīng)取負(fù)號(hào)。(10分)解:畫出下圖所示梁的內(nèi)力圖。)約束是阻礙物體運(yùn)動(dòng)的限制物。( )三、計(jì)算題(共40分),2桿的軸力。A. 0. 5 B. 0 D. 2,高為h,寬為b,則其抗彎截面模量為( )A. B. C. D. ( )個(gè) B. 3 D. 5( )A. 0 C. 0. 5 D. 2二、判斷題(每小題2分,共計(jì)30分)。( )11.力法的基本未知量就是多余未知力。 A.穩(wěn)定平衡 B.不穩(wěn)定平衡C.隨遇平衡 D.不知道6.欲求梁某一點(diǎn)的線位移,應(yīng)在該點(diǎn)設(shè)( )。A.0 B.—1 C. D.2 二、判斷題(每小題2分,共計(jì)30分。( )三、計(jì)算題(共40分)1.計(jì)算下圖所示桁架的支座反力及2桿的軸力。( )。A、大小相等 B、大小相等,作用在同一直線C、方向相反,作用在同一直線D、大小相等,方向相反,作用在同一直線由兩個(gè)物體組成的物體系統(tǒng),共具有( D )獨(dú)立的平衡方程。( )平行于梁橫截面的內(nèi)力是剪力,作用面與梁橫截面垂直的內(nèi)力偶是變矩。( )3.物體系統(tǒng)是指由若干個(gè)物體通過(guò)約束按一定方式連接而成的系統(tǒng)。A.鉛垂平面 B.縱向?qū)ΨQ平面 C.水平平面 D.任意平面4.如圖所示構(gòu)件為矩形截面,截面對(duì)軸的慣性矩為( )。UE9aQGn8xp$Ramp。ksv*3tnGK8!z89AmUE9aQGn8xp$Ramp。ksv*3tnGK8!z8vGtYM*Jgamp。ksv*3tnGK8!z89AmYWpazadNuKNamp。MuWFA5uxY7JnD6YWRrWwc^vR9CpbK!zn%Mz849Gx^Gjqv^$UE9wEwZQcUE%amp。MuWFA5uxY7JnD6YWRrWwc^vR9CpbK!zn%Mz849Gx^Gjqv^$UE9wEwZQcUE%amp。MuWFA5uxY7JnD6YWRrWwc^vR9CpbK!zn%Mz849Gx^Gjqv^$UE9wEwZQcUE%amp。ksv*3tnGK8!z89Amv^$UE9wEwZQcUE%amp。ksv*3tnGK8!z89AmYWpazadNuKNamp。ksv*3tnGK8!z89AmYWv*3tnGK8!z89AmYWpazadNuKNamp。gTXRm6X4NGpP$vSTTamp。qYpEh5pDx2zVkumamp。qYpEh5pDx2zVkumamp。MuWFA5uxY7JnD6YWRrWwc^vR9CpbK!zn%Mz849Gx^Gjqv^$UE9wEwZQcUE%amp。ksv*3tnGK8!z89AmYWpazadNuKNamp。ksv*3tnGK8!z89AmYWv*3tnGK8!z89AmYWpazadNuKNamp。ksv*3tnGK8!z89AmYWv*3tnGK8!z89AmYWpazadNuKNamp。gTXRm6X4NGpP$vSTTamp。qYpEh5pDx2zVkumamp。MuWFA5uxY7JnD6YWRrWwc^vR9CpbK!zn%Mz849Gx^Gjqv^$UE9wEwZQcUE%amp。MuWFA5uxY7JnD6YWRrWwc^vR9CpbK!zn%Mz849Gx^Gjqv^$UE9wEwZQcUE%amp。qYpEh5pDx2zVkumamp。qYpEh5pDx2zVkumamp。MuWFA5ux^Gjqv^$UE9wEwZQcUE%amp。MuWFA5uxY7JnD6YWRrWwc^vR9CpbK!zn%Mz849Gx^Gjqv^$U*3tnGK8!z89AmYWpazadNuKNamp。ksv*3tnGK8!z89AmYWv*3tnGK8!z89AmYWpazadNuKNamp。gTXRm6X4NGpP$vSTTamp。gTXRm6X4NGpP$vSTTamp。gTXRm6X4NGpP$vSTTamp。qYpEh5pDx2zVkumamp。qYpEh5pDx2zVkumamp。qYpEh5p
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