【正文】 mov cx,10ag2:mov ax,[bx] call disp add bx,2 loop ag2 call crlf lea dx,m2 call dispstr mov ax,max call disp call crlf lea dx,m3 call dispstr mov ax,min call disp call crlf MOV AH,4CH INT 21Hdisp proc push bx push cx mov cx,0 mov bx,2 mov dx,0lp3: cmp ax,0 jz lp4 div bx push dx mov dx,0 inc cx jmp lp3lp4: cmp cx,0 jz exit pop dx add dl,30h mov ah,2 int 21h loop lp4 mov dl,39。data endscode segment assume ss:stack,cs:code,ds:datastart: mov ax,0 mov es,ax mov ax,seg ir mov es:0072h,ax mov ax,offset ir mov es:0070h,ax jmp $ mov ah,4ch int 21hir proc near mov ax,seg str mov ds,ax mov dx,offset str mov ah,9 int 21h iretir endpcode ends end start 。Code2222INTax=*p。 a=c xchg ax,c mov a,axnext2:mov ax,b cmp ax,c jge next3 。 stosb int 3 mov ah,4ch int 21hend start 18. 移位指令：(bx)=84f0H,把(bx)中的16位數(shù)每4位壓入堆棧（逆序）.model small.data.stack dw 100h.codestart:mov ch,4 mov cl,4 mov bx,84f0hnext: ror bx,cl mov ax,bx and ax,0f000h push ax dec ch jnz next pop ax pop bx pop cx pop dx mov al,4ch int 21hend start19. JMP指令.model small.stack 100h.codestart: mov ax,1 jmp a4 a2: mov bx,2 jmp a5 a3: mov cx,3 jmp a2 a4: mov dx,4 jmp a3 a5: int 3end start20. JZ條件轉(zhuǎn)移指令：.model small.stack 100h.codestart:mov al,39。a39。aabaa39。xpsqm39。ENDAH,ES,AXPTRE_SEG15893D_SEGhello,39。 wVarA DW 011B,32678,65535,0FH,2,5+7ACH,39。,0FH,1 DB 2*56,39。439。539。.stack dw 100h.codestart:mov ax,data mov ds,ax mov dl,str+2 mov ah,2 int 21h mov dl,str+11 mov ah,2 int 21h lea dx,str mov ah,9 int 21h mov ah,4ch int 21hend start4. 完整段匯編程序結(jié)構(gòu)寫一個完整的程序放在代碼段C_SEG中，要求把數(shù)據(jù)段D_SEG中的DADD1和附加段E_SEG中的DADD2相加，并把結(jié)果存放在D_SEG段中的SUM中。D_SEGMOVAXES:DADD2+2C_SEGSEGMENTY_SEGENDSCS:Code,DS:X_SEG,ES:Y_SEG,SS:Z_SEGAX[BP+Z](v(x*y+z540))/x mov ah,4ch int 21hend start9. XLAT查表指令：字符串加密.model small.data s1 db 39。 rep stosb mov byte ptr es:[di],39。039。A39。 X=Y JMP BB AA: MOV BX,AX BB: MOV Z,BX mov ah,4ch int 21hend start22. 兩個數(shù)，求大數(shù)。the min