【正文】 i,j,t。a[i][1],amp。39。while(nn++。printf(“which character that begin to copy?”)。printf(“n”)。if(max==number)max=min。}void max_min_value(int *number){int *max,*min,*p,temp。input(number)。strcpy(p,p1)。gets(str2)。p=*p1。p3=amp。} if(sign==1 || loca==1)printf(“%d not been ”,n)。while((sign==1)amp。for(i=0。jif(num[min]num[j])min=j。printf(“input name: ”)。||c==39。scanf(“%d”,amp。include include define N 10void main(){ void input(int [],char name[][8])。sumx=。for(i=0。for(j=0。} }void aver_stu(void){ int i,j。cour2cour3 cour4cour5printf(“highest:%NO.%2dcourse %2dn”,h,r,c)。for(j=0。void aver_stu(void)。include define N 10 define M 5 float score[N][M]。j++。o39。e39。for(i=0,j=0。}77 寫(xiě)一個(gè)函數(shù)，將字符竄中元音字母復(fù)制到另一個(gè)字符竄，然后輸出。39。scanf(“%s”,s1)。for(i=0,j=strlen(str)。include include char str[100]。printf(“n”)。for(i=0。void main(){void convert(int array[][3])。if(prime(n))printf(“n %d is a ”,n)。}void smaller_than_zero(float a,float b){ p=b/(2*a)。printf(“x1=%fttx2=%fn”,x1,x2)。scanf(“%f,%f,%f”,amp。} 72 求方程ax*x+bx+c=0的根，用3個(gè)函數(shù)分別求當(dāng)b*b4ac大于0，等于0、小于0時(shí)的根并輸出結(jié)果。}int hcf(int u,int v){ int t,r。int u,v,h,l。int lcd(int,int,int)。printf(“=%dn”,l)。}int lcd(int u,int v,int h){ return(u*v/h)。printf(“input a,b,c:”)。if(disc0){greater_than_zero(a,b)。} void equal_to_zero(float a,float b){ x1=x2=(b)/(2*a)。n)。include define N 3 int array[N][N]。printf(“noriginal array :n”)。jprintf(“%5d”,array[i][j])。} }75 寫(xiě)一個(gè)函數(shù)，是輸入的字符串按反序存放，在主函數(shù)中輸入和輸出字符竄。int i,j。printf(“input string1:”)。string1[i]!=39。39。}void cpy(char s[],char c[]){int i,j。||s[i]==39。||s[i]==39。){c[j]=s[i]。4 計(jì)算平均方差。void input_stu(void)。iprintf(“n NO %2d ”,i+1)。h=highest()。score[i][j])。float s。high=score[0][0]。float sumx,sumxn。要求輸入一個(gè)職工號(hào)，用折半查找法找出該職工的姓名，從主函數(shù)輸入要查找的職工號(hào)，輸出該職工姓名。while(flag==1){printf(“ninput number to look for:”)。N39。num[i])。for(j=i。}printf(“n result:n”)。if((nnum[N1]))loca=1。elsetop=mid+1。b。} void swap(int*p1,int*p2){ int p。gets(str1)。}void swap(char *p1,char *p2){ char p[20]。int number[10]。number[i])。*min=temp。pprintf(“%d ”,*p)。gets(str1)。n=0。} *p2=39。a[i][0],amp。iprintf(“%d %d %dn”,a[i][0],a[i][1],a[i][2])。include void main(){ void sort(char *p,int m)。iscanf(“%d”,amp。printf(“n”)。*p2=temp。printf(“input year,month,day:”)。break。break。break。amp。void main(){ int i,days。for(i=1。printf(“%d/%d is the in %”,days,)。for(i=0。scanf(“%d”,amp。for(j=0。void main(){ void input(struct student stu[])。scanf(“%s”,stu[i].num)。} }void print(struct student stu[6]){ int i,j。char name[8]。printf(“NO.:”)。} }average=0。average+=stu[i].avr。printf(”%“,stu[i].avr)。二、王老師請(qǐng)同學(xué)們?cè)诤诎迳袭?huà)圓和三角形，用意是什么？文章中的這些描寫(xiě)，在結(jié)構(gòu)和內(nèi)容表達(dá)上有什么作用？王老師請(qǐng)同學(xué)們?cè)诤诎迳袭?huà)圓和三角形，用意是讓同學(xué)們明白只要功夫深，鐵棒可以磨成針！要大家牢記一種熱愛(ài)知識(shí)和持之以恒的學(xué)習(xí)精