信源的率失真函數(shù)ppt課件(更新版)
【正文】 d ??失真函數(shù)),(x?)x(S1dxe)x(p)x()1( )x?,x(Sd ???????? ??? 的求含由)x(p)S(f)x(S ??的設(shè)含222)x(2e21)x(p)xX(p),(xX??????????????高斯信源第 7章 信源的率失真函數(shù) ??????????? ????????????S)S(f1S)S(fdxe)S(f2dxe)S(fdxe)x(p)x(0)x?x(S)x?x(S)x?,x(Sd22)x(pS)x(p)S(f)x( ????? 22222x22x2 eS2e2S ?? ????????第 7章 信源的率失真函數(shù) ),(x)x?(pS)x(/1x?de)x?(p)2( )x?,x(Sd ??????? ??? 的求含由)x(px?de)x?(pSx?de)x?(p)S(f 22 )x?x(S)x?x(S ?? ???????? ????2)x?x(SeS)x?x(g ?????記)x(px?d)x?x(g)x?(p ??? ???)(P)(G)(P xx? ????第 7章 信源的率失真函數(shù) 2xj2x2x2222edxee21)(P ?????????????? ?S4xj)x?x(S22 edxeeS)G( ?????? ????? ?)S2 1(2S42xx?22222ee)G( )(P )(P ???????????????)S21(2x?222e)S21(21)x?(p ???????第 7章 信源的率失真函數(shù) ),(x?),(xe)x?(p)x()x/x?(pS)3( )x?,x(SdD??????????的含22222)x?x(S)S21(2x?22x2D ee)S21(21eS2)x/x?(p ???????????)S21(2)x?x()S21(2x?2x2222222eee)S21)(S21(2?????????????第 7章 信源的率失真函數(shù) )S21(2z)S21(2)x?x(DD22e)S21(21e)S21(21)x?(p)x(p)x/x?(p)x?/x(p????????????方差為 1/2S的反向高斯加性信道 Z ZX?X ?? X?第 7章 信源的率失真函數(shù) ? ??? ??? dx)x(l o g)x(pSD)D(RS)4( 的含)e2l og (21Sl ogSDdx)x(pl og)x(pdxSl og)x(pSDdx)x(pSl og)x(pSD2????????????????????????????第 7章 信源的率失真函數(shù) Sx?d x d)x?,x(d)x/x?(p)x(pDDS)5( D 求的由含 ? ???? ?????S21x?dz dzee)S21(2)S21(212)S21(2x?)S21(2z2222???????? ? ????????????? ?? ????????????????x?dx d)x?x)(x?/x(p)x?(px?dx d)x?,x(d)x/x?(p)x(pD2DD第 7章 信源的率失真函數(shù) D21S ??),(x?),(x)x/x?(p)D(RS)6( D ????????和的不含DPl og21Dl og21)e2l og (21)eD2l og (21)e2l og (21D21l og21)e2l og (21Sl ogSD)D(R2222???????????????????????第 7章 信源的率失真函數(shù) D2z)S21(2zD22eD21e)S21(21)x?/x(p????????方差為 D的反向高斯加性信道 第 7章 信源的率失真函數(shù) 0DPlog21)D(R ??0)P(R)D(R0DD)0(R)D(R0DDm a xm a xm i nm i n?????????，當(dāng)，當(dāng)PR(D) D 0
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