【正文】 始標(biāo)志 (一個(gè) 1后連續(xù) 15個(gè) 0) ? 移動(dòng)臺(tái)開始用沃氏碼解調(diào)信號(hào) 00...01 00...01 00...01 00...01 00...01 00...01 00...01 導(dǎo)頻信道 (Walsh Code 0) Course 809 Lesson 3: CDMA前向信道 (January 1998) 30 CDMA概述 第三課 : CDMA前向信道 3b: 導(dǎo)頻信道 復(fù)習(xí) Course 809 Lesson 3: CDMA前向信道 (January 1998) 31 3b: Review Questions 1. What is the Pilot Channel? The pilot channel is a reference channel which the mobile station uses for acquisition, timing, and as phase reference for coherent demodulation. It is transmitted at all times by each base station on each active CDMA frequency. This signal is tracked continuously by each mobile station. 2. Discuss the frame structure of the Pilot Channel. The Pilot Channel carries no data。 and so on, up to a maximum of 7 Paging Channels per CDMA frequency. 3. List the names of all the Overhead Messages transmitted on the Paging Channel. System Parameters Message, Access Parameters Message, CDMA Channel List Message, Extended System Parameters Message, Extended Neighbor List Message, and Global Service Redirection Message. 。只有協(xié)議版本大于或等于該域的移動(dòng)臺(tái)才能接入系統(tǒng)。 ? 區(qū)別 : ?每幀比特率增加了 ?所有幀均需完成 CRC ? 每一幀中的第一位保留 ?目前，第一位不用 267 12 8 288 bits (20 ms) F T 14400 bps Frame Information Bits Full Rate 144 bits (20 ms) F T 7200 bps Frame Information Bits 1/2 Rate 8 72 bits (20 ms) T 3600 bps Frame Information Bits 1/4 Rate 36 bits (20 ms) T 1800 bps Frame Information Bits 1/8 Rate 注 解 R 保留位 F 幀質(zhì)量指示 (CRC) T 編碼尾比特 8 1 1 125 10 8 125 8 10 1 R R R R F F 55 125 10 8 21 8 6 1 Course 809 Lesson 3: CDMA前向信道 (January 1998) 19 多路復(fù)用選擇 2 ? 與多路復(fù)用選擇 1功能相同。 1 2 5 4 9 7 3 9 7 1 2 1 1 4 5 1 6 9 1 9 3 2 1 7 2 4 1 2 6 5 2 8 9 3 1 3 3 3 7 3 6 12 2 6 5 0 7 4 9 8 1 2 2 1 4 6 1 7 0 1 9 4 2 1 8 2 4 2 2 6 6 2 9 0 3 1 4 3 3 8 3 6 23 2 7 5 1 7 5 9 9 1 2 3 1 4 7 1 7 1 1 9 5 2 1 9 2 4 3 2 6 7 2 9 1 3 1 5 3 3 9 3 6 34 2 8 5 2 7 6 1 0 0 1 2 4 1 4 8 1 7 2 1 9 6 2 2 0 2 4 4 2 6 8 2 9 2 3 1 6 3 4 0 3 6 45 2 9 5 3 7 7 1 0 1 1 2 5 1 4 9 1 7 3 1 9 7 2 2 1 2 4 5 2 6 9 2 9 3 3 1 7 3 4 1 3 6 56 3 0 5 4 7 8 1 0 2 1 2 6 1 5 0 1 7 4 1 9 8 2 2 2 2 4 6 2 7 0 2 9 4 3 1 8 3 4 2 3 6 67 3 1 5 5 7 9 1 0 3 1 2 7 1 5 1 1 7 5 1 9 9 2 2 3 2 4 7 2 7 1 2 9 5 3 1 9 3 4 3 3 6 78 3 2 5 6 8 0 1 0 4 1 2 8 1 5 2 1 7 6 2 0 0 2 2 4 2 4 8 2 7 2 2 9 6 3 2 0 3 4 4 3 6 89 3 3 5 7 8 1 1 0 5 1 2 9 1 5 3 1 7 7 2 0 1 2 2 5 2 4 9 2 7 3 2 9 7 3 2 1 3 4 5 3 6 91 0 3 4 5 8 8 2 1 0 6 1 3 0 1 5 4 1 7 8 2 0 2 2 2 6 2 5 0 2 7 4 2 9 8 3 2 2 3 4 6 3 7 01 1 3 5 5 9 8 3 1 0 7 1 3 1 1 5 5 1 7 9 2 0 3 2 2 7 2 5 1 2 7 5 2 9 9 3 2 3 3 4 7 3 7 11 2 3 6 6 0 8 4 1 0 8 1 3 2 1 5 6 1 8 0 2 0 4 2 2 8 2 5 2 2 7 6 3 0 0 3 2 4 3 4 8 3 7 21 3 3 7 6 1 8 5 1 0 9 1 3 3 1 5 7 1 8 1 2 0 5 2 2 9 2 5 3 2 7 7 3 0 1 3 2 5 3 4 9 3 7 31 4 3 8 6 2 8 6 1 1 0 1 3 4 1 5 8 1 8 2 2 0 6 2 3 0 2 5 4 2 7 8 3 0 2 3 2 6 3 5 0 3 7 41 5 3 9 6 3 8 7 1 1 1 1 3 5 1 5 9 1 8 3 2 0 7 2 3 1 2 5 5 2 7 9 3 0 3 3 2 7 3 5 1 3 7 51 6 4 0 6 4 8 8 1 1 2 1 3 6 1 6 0 1 8 4 2 0 8 2 3 2 2 5 6 2 8 0 3 0 4 3 2 8 3 5 2 3 7 61 7 4 1 6 5 8 9 1 1 3 1 3 7 1 6 1 1 8 5 2 0 9 2 3 3 2 5 7 2 8 1 3 0 5 3 2 9 3 5 3 3 7 71 8 4 2 6 6 9 0 1 1 4 1 3 8 1 6 2 1 8 6 2 1 0 2 3 4 2 5 8 2 8 2 3 0 6 3 3 0 3 5 4 3 7 81 9 4 3 6 7 9 1 1 1 5 1 3 9 1 6 3 1 8 7 2 1 1 2 3 5 2 5 9 2 8 3 3 0 7 3 3 1 3 5 5 3 7 92 0 4 4 6 8 9 2 1 1 6 1 4 0 1 6 4 1 8 8 2 1 2 2 3 6 2 6 0 2 8 4 3 0 8 3 3 2 3 5 6 3 8 02 1 4 5 6 9 9 3 1 1 7 1 4 1 1 6 5 1 8 9 2 1 3 2 3 7 2 6 1 2 8 5 3 0 9 3 3 3 3 5 7 3 8 12 2 4 6 7 0 9 4 1 1 8 1 4 2 1 6 6 1 9 0 2 1 4 2 3 8 2 6 2 2 8 6 3 1 0 3 3 4 3 5 8 3 8 22 3 4 7 7 1 9 5 1 1 9 1 4 3 1 6 7 1 9 1 2 1 5 2 3 9 2 6 3 2 8 7 3 1 1 3 3 5 3 5 9 3 8 32 4 4 8 7 2 9 6 1 2 0 1 4 4 1 6 8 1 9 2 2 1 6 2 4 0 2 6 4 2 8 8 3 1 2 3 3 6 3 6 0 3 8 41 6 C o l u m n s24 rowsCourse 809 Lesson 3: CDMA前向信道 (January 1998) 12 9600bps塊交織器 (輸出陣列 ) ? 現(xiàn)在， 9600bps的數(shù)據(jù)不再相關(guān) ? 相鄰碼符號(hào)從時(shí)間上隔離開了 ? 突發(fā)差錯(cuò)的影響減少了 ?低速重復(fù)的碼符號(hào)被隔離開了。 ?每個(gè)信息比特與多個(gè)符號(hào)的產(chǎn)生有關(guān)。Course 809 Lesson 3: CD