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施工現(xiàn)場臨時用電專項方案培訓資料(完整版)

2025-06-15 08:30上一頁面

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【正文】 Pe = n P (εe/ε)^ = ( / )^ = Ij1 = Kx Pe / ( Ue cosφ) = 1000 / ( 380 ) = Pjs = Kx Pe = = Qjs = Pjs tgφ = = (3)鋼筋套絲機Kx = ,Cosφ = ,tgφ = (1 Cosφ^2)^(1 ^2)^ / = Pe = n P (εe/ε)^ = ( / )^ = Ij1 = Kx Pe / ( Ue cosφ) = 1000 / ( 380 ) = Pjs = Kx Pe = = Qjs = Pjs tgφ = = (4)鋼筋箍筋彎曲機Kx = ,Cosφ = ,tgφ = (1 Cosφ^2)^(1 ^2)^ / = Pe = n P (εe/ε)^ = ( / )^ = Ij1 = Kx Pe / ( Ue cosφ) = 1000 / ( 380 ) = Pjs = Kx Pe = = Qjs = Pjs tgφ = = (5)數(shù)控鋼筋調(diào)直切斷機Kx = ,Cosφ = ,tgφ = (1 Cosφ^2)^(1 ^2)^ / = Pe = n P (εe/ε)^ = ( / )^ = Ij1 = Kx Pe / ( Ue cosφ) = 1000 / ( 380 ) = Pjs = Kx Pe = = Qjs = Pjs tgφ = = (6)電動切割機Kx = ,Cosφ = ,tgφ = (1 Cosφ^2)^(1 ^2)^ / = Pe = n P (εe/ε)^ = ( / )^ = Ij1 = Kx Pe / ( Ue cosφ) = 1000 / ( 380 ) = Pjs = Kx Pe = = Qjs = Pjs tgφ = = (7)木工圓鋸Kx = ,Cosφ = ,tgφ = (1 Cosφ^2)^(1 ^2)^ / = Pe = n P (εe/ε)^ = ( / )^ = Ij1 = Kx Pe / ( Ue cosφ) = 1000 / ( 380 ) = Pjs = Kx Pe = = Qjs = Pjs tgφ = = (8)木工平刨床Kx = ,Cosφ = ,tgφ = (1 Cosφ^2)^(1 ^2)^ / = Pe = n P (εe/ε)^ = ( / )^ = Ij1 = Kx Pe / ( Ue cosφ) = 1000 / ( 380 ) = Pjs = Kx Pe = = Qjs = Pjs tgφ = = (9)LED泛光燈照明Kx = ,Cosφ = ,tgφ = (1 Cosφ^2)^(1 ^2)^ / = Pe = n P (εe/ε)^ = ( / )^ = Ij1 = Kx Pe / ( Ue cosφ) = 1000 / ( 380 ) = Pjs = Kx Pe = = Qjs = Pjs tgφ = = (10)62號二級配電箱計算負荷用電設(shè)備同期使用系數(shù)Kx=;Ijs = Kx ΣPe / ( Ue Cosφ) = 1000 / ( 380 ) = ;,故:Ijs = max{,max(,)} = 163號二級配電箱設(shè)備用電負荷(1)插入式振動器Kx = ,Cosφ = ,tgφ = (1 Cosφ^2)^(1 ^2)^ / = Pe = n P (εe/ε)^ = ( / )^ = Ij1 = Kx Pe / ( Ue cosφ) = 1000 / ( 380 ) = Pjs = Kx Pe = = Qjs = Pjs tgφ = = (2)直流電焊機Kx = ,Cosφ = ,tgφ = (1 Cosφ^2)^(1 ^2)^ / = Pe = n P (εe/ε)^ = ( / )^ = Ij1 = Kx Pe / ( Ue cosφ) = 1000 / ( 380 ) = Pjs = Kx Pe = = Qjs = Pjs tgφ = = (3)沖擊錘鉆Kx = ,Cosφ = ,tgφ = (1 Cosφ^2)^(1 ^2)^ / = Pe = n P (εe/ε)^ = ( / )^ = Ij1 = Kx Pe / ( Ue cosφ) = 1000 / ( 380 ) = Pjs = Kx Pe = = Qjs = Pjs tgφ = = (4)樓層各種照明Kx = ,Cosφ = ,tgφ = (1 Cosφ^2)^(1 ^2)^ / = Pe = n P (εe/ε)^ = ( / )^ = Ij1 = Kx Pe / ( Ue cosφ) = 1000 / ( 380 ) = Pjs = Kx Pe = = Qjs = Pjs tgφ = = (5)63號二級配電箱計算負荷用電設(shè)備同期使用系數(shù)Kx=;Ijs = Kx ΣPe / ( Ue Cosφ) = 1000 / ( 380 ) = ;,故:Ijs = max{,max(,)} = 12一級配電柜計算負荷總的計算負荷計算,總配電箱用電設(shè)備同期使用系數(shù)取Kx = 總的有功功率: Pjs = KxΣPjs = = 總的無功功率: Qjs = KxΣQjs = = 總的視在功率: Sjs = (Pjs^2 + Qjs^2)^ = ( + )^ = 總的計算電流計算:Ijs = Sjs 1000 /( Ue) = 1000 / ( 380) = 同時要求2,故:Ijs = max{,max(,)} = 17二級配電箱設(shè)備用電負荷(1)辦公設(shè)備用電Kx = ,Cosφ = ,tgφ = (1 Cosφ^2)^(1 ^2)^ / = Pe = n P (εe/ε)^ = ( / )^ = Ij1 = Kx Pe / ( Ue cosφ) = 1000 / ( 380 ) = Pjs = Kx Pe = = Qjs = Pjs tgφ = = (2)辦公照明用電Kx = ,Cosφ = ,tgφ = (1 Cosφ^2)^(1 ^2)^ / = Pe = n P (εe/ε)^ = ( / )^ = Ij1 = Kx Pe / ( Ue cosφ) = 1000 / ( 380 ) = Pjs = Kx Pe = = Qjs = Pjs tgφ = = (3)7二級配電箱計算負荷用電設(shè)備同期使用系數(shù)Kx=;Ijs = Kx ΣPe / ( Ue Cosφ) = 1000 / ( 380 ) = ;,故:Ijs = max{,max(,)} = 18二級配電箱設(shè)備用電負荷(1)生活電器用電Kx = ,Cosφ = ,tgφ = (1 Cosφ^2)^(1 ^2)^ / = Pe = n P (εe/ε)^ = ( / )^ = Ij1 = Kx Pe / ( Ue cosφ) = 1000 / ( 380 ) = Pjs = Kx Pe = = Qjs = Pjs tgφ = = (2)生活照明用電Kx = ,Cosφ = ,tgφ = (1 Cosφ^2)^(1 ^2)^ / = Pe = n P (εe/ε)^ = ( / )^ = Ij1 = Kx Pe / ( Ue cosφ) = 1000 / ( 380 ) = Pjs = Kx Pe = = Qjs = Pjs tgφ = = (3)8二級配電箱計算負荷用電設(shè)備同期使用系數(shù)Kx=;Ijs = Kx ΣPe / ( Ue Cosφ) = 1000 / ( 380 ) = ;,故:Ijs = max{,max(,)} = 13一級配電柜計算負荷總的計算負荷計算,總配電箱用電設(shè)備同期使用系數(shù)取Kx = 總的有功功率: Pjs = KxΣPjs = = 總的無功功率: Qjs = KxΣQjs = = 總的視在功率: Sjs = (Pjs^2 + Qjs^2)^ = ( + )^ = 總的計算電流計算:Ijs = Sjs 1000 /( Ue) = 1000 / ( 380) = 同時要求3,故:Ijs = max{,max(,)} = 二、 導線及開關(guān)箱內(nèi)電氣設(shè)備選擇1號干線上導線及開關(guān)箱內(nèi)電氣設(shè)備選擇、1塔式起重機導線及開關(guān)箱內(nèi)電氣設(shè)備選擇根據(jù)計算負荷,知1塔式起重機計算電流為:Ij1 = KxPe/(Uecosφ) = (1)選擇BLX325+216,安全載流量為110A≥。一級配電柜與二級配電箱之間電纜場地情況選擇穿管埋設(shè)方式。+2*35mm178。5. 施工作業(yè)人員入場教育(1) 施工用電作業(yè)人員先必須經(jīng)過項目安全員、主管工長、機管員、勞資員及保衛(wèi)組織的項目安全常識系統(tǒng)教育,并建立相應(yīng)的檔案資料。擬從配電房設(shè)置一個主線路到總配電室;3號4號庫共用1一級配電柜,5號6號庫共用2一級配電柜、辦公區(qū)和生活區(qū)共用3一級配電柜;各一級配電柜分別設(shè)置4條線路至固定二級配電箱(鋼筋加工場地配電箱和塔吊配電箱)和2條線路至各棟物流庫樓層的移動二級配電箱(樓層用電配電箱)。2. 本工程按項目總的進度計劃結(jié)合本方案第五章第一條第7點和第14點和17點計算結(jié)果,滿足施工需求。局部區(qū)域設(shè)置有辦公及設(shè)備夾層。安全目標:堅持“安全第一、預防為主”的工作方針,確保無重大工傷事故,輕傷頻率控制在4‰以內(nèi)。6. XX負責施工用電材料的采購;XX負責施工用電的施工及管理;質(zhì)檢員負責對現(xiàn)場施工用電質(zhì)量進行監(jiān)督管理并進行相關(guān)報驗工作安全總監(jiān)、安全員主要負責施工用電的安全管理;7. 同時施工用電總承包管理機構(gòu)各成員均需對施工用電的安全進行管理。(3) 針對施工過程中階段性出現(xiàn)的具有的特定性的安全問題及隱患,機管員必須現(xiàn)場作針對性交底,并形成相關(guān)記錄。電纜鋁芯絕緣電纜m800mVLV3*25mm178。一、 參數(shù)設(shè)置(1)1一級配電柜參數(shù)用電接駁方式由總配電室接入一級配電柜編號1一級配電柜一級配電柜距接駁點布線距離Lo(m)20一級配電柜的同期使用系數(shù)Kx分配電箱數(shù)量6導線線芯材料鋁線一級配電柜進線敷設(shè)方式埋地暗敷二級配電箱進線敷設(shè)方式埋地暗敷設(shè)備電線敷設(shè)方式埋地暗敷/架空線路干線允許電壓降%5(2)2一級配電柜參數(shù)用電接駁方式由總配電室接入一級配電柜編號2一級配電柜一級配電柜距接駁點布線距離Lo(m)20一級配電柜的同期使用系數(shù)Kx分配電箱數(shù)量6導線線芯材料鋁線一級配電柜進線敷設(shè)方式埋地暗敷二級配電箱進線敷設(shè)方式埋地暗敷設(shè)備電線敷設(shè)方式埋地暗敷/架空線路干線允許電壓降%5(3)3一級配電柜參數(shù)用電接駁方式由總配電室接入一級配電柜編號3一級配電柜一級配電柜距接駁點布線距離Lo(m)20一級配電柜的同期使用系數(shù)Kx分配電箱數(shù)量2導線線芯材料鋁線一級配電柜進線敷設(shè)方式埋地暗敷二級配電箱進線敷設(shè)方式埋地暗敷設(shè)備電線敷設(shè)方式埋地暗敷/架空線路干線允許電壓降%10總箱編號干線名稱分配電箱編號安裝部位同期使用系數(shù)Kx(m)功率因素Cosφ分箱到一級配電箱布線距離1一級配電柜1號干線31號二級配電箱3物流庫塔吊70m2號干線32號二級配電箱3物流庫鋼筋、木工加工區(qū)150m3號干線33號二級配電箱3物流庫樓層120m4號干線41號二級配電箱4物流庫塔吊70m5號干線42號二級配電箱4物流庫鋼筋、木工加工區(qū)150m6號干線43號二級配電箱4物流庫樓層
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