【正文】 9cm focal length. The lens projects an image of the object onto a screen 14cm away. What is the diameter of the exit pupil?l’lImageLensStopObjectSolution. Refer to the figure. First, from the known focal length and the image distance, we find the object distance. and l’=14 f’=9 l=(cm)The stop is onehalf that distance is front of the lens, so ls=(cm) ∴l(xiāng)s’=(cm) ∴2. Two lenses, a lens of focal length and a minus lens of unknown power, are mounted coaxially and 8 cm apart. The system is a focal, that is light entering the system parallel at one side emerges parallel at the other. If a stop 15mm in diameter is placed halfway between the lenses: 1) Where is the entrance pupil? 2) Where is the exit pupil? 3) What are their diameters? F1’(F2)l2’L1’Stopf’=8cmSolution. Refer to the figure. For the system to be a focal, the focal points of the two lenses must coincide. Since f1’=, and the two lenses are 8cm apart, so f2’=. The entrance pupil is the image of stop formed by the first lens. According to Gauss’s equation, and l1’=4cm, f1’=. We get The exit pupil’s location is　　　　返回　　English Homework for Chapter 7　1. A person wants to look at the image of his or her own eyes, without acmodation, using a concave mirror of 60cm radius of curvature. How far must the mirror be from the eye if the person has1) Normal vision?2) 4diopter myopia, without correction?3) 4diopter hyperopia, without correction?Solution.1) When the person has normal vision, according to the following scheme 1, we get l39。2) the microscope is used for visual observation. 　　返回　工程光學(xué)（上）期末考試試卷一．問(wèn)答題：（共12分，每題3分）1．?dāng)z影物鏡的三個(gè)重要參數(shù)是什么？它們分別決定系統(tǒng)的什么性質(zhì)？2．為了保證測(cè)量精度，測(cè)量?jī)x器一般采用什么光路？為什么？3．顯微物鏡、望遠(yuǎn)物鏡、照相物鏡各應(yīng)校正什么像差？為什么？4．評(píng)價(jià)像質(zhì)的方法主要有哪幾種？各有什么優(yōu)缺點(diǎn)？二．圖解法求像或判斷成像方向：（共18分，每題3分）1．求像A39。3．求物AB經(jīng)理想光學(xué)系統(tǒng)后所成的像，并注明系統(tǒng)像方的基點(diǎn)位置和焦距4．判斷光學(xué)系統(tǒng)的成像方向5．求入瞳及對(duì)無(wú)窮遠(yuǎn)成像時(shí)50%漸暈的視場(chǎng)6．判斷棱鏡的成像方向三．填空：（共10分，每題2分） 1．照明系統(tǒng)與成像系統(tǒng)之間的銜接關(guān)系為：①________________________________________________②________________________________________________2．轉(zhuǎn)像系統(tǒng)分____________________和___________________兩大類，其作用是：_________________________________________3．一學(xué)生帶500度近視鏡，則該近視鏡的焦距為_(kāi)________________,該學(xué)生裸眼所能看清的最遠(yuǎn)距離為_(kāi)________________。（10分）2．已知，的雙凸透鏡，置于空氣中。（20分）