【正文】
in(10)( ??? tty 因此系統(tǒng)的輸入信號為 9 ) r c t a n4530s in (136)4530s in (13610)4530c os (1366136)4530s in (10)4530c os (6)4530s in (1030)4530s in ()()()(????????????????????????????????ttttttttydttdytx ? 2 求周期信號 )451 0 0c o s ( o )( ???? tttx 通 過 傳 遞 函數(shù) 為 1)( ?? ssH 的系統(tǒng)后所得到的穩(wěn)態(tài)響應 )(ty 。 0)(1 00 ?? ?T dttxTa ,定積分的幾何含義 ???????? ???? ? ?? 20 20 c o sc o s2c o s)(2 T TTTn t d tnAt d tnATt d tntxTa ??? 令 tns ?? ,則 x(t) t O T/2 T A A 7 ???????? ??????????? ?????????????????? ?TnTnTnTn TnTnns dss dsTn AnssdAnssdATa???? ?????22020 2c osc os2c osc os2 式中T?? 2? 02s in0s in ????????? ?? ???? nnsnsn Aa n 同理,???????? ??? ???? nnsnsnAb n 2c os0c os 當 n為奇數(shù)時, ?nAbn 4? 當 n為偶數(shù)時, 0?nb 因此 ?????? ????? ?????tttAtnn Atxn?????? 5s in513s in31s in4s in4)(,5,3,1 8 四 計算題( 15分) 1 已